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x^2-60x=-450
We move all terms to the left:
x^2-60x-(-450)=0
We add all the numbers together, and all the variables
x^2-60x+450=0
a = 1; b = -60; c = +450;
Δ = b2-4ac
Δ = -602-4·1·450
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30\sqrt{2}}{2*1}=\frac{60-30\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30\sqrt{2}}{2*1}=\frac{60+30\sqrt{2}}{2} $
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